Image.open() cannot identify image file in python script file -
i trying execute script
from pil import image im = image.open("image.jpg") nx, ny = im.size
it working fine when run in python shell
pytesser_v0.0.1]#env python >>> pil import image >>> im = image.open("image.jpg") <pil.jpegimageplugin.jpegimagefile image mode=rgb size=46x24 @ 0x7fa4688f16d0>
but when put in test.py file , run python test.py getting error
file "test1.py", line 17, in <module> im = image.open("image.jpg") file "/usr/local/python.2.7.11/lib/python2.7/site-packages/pil/image.py", line 2309, in open % (filename if filename else fp)) ioerror: cannot identify image file 'image.jpg'
please me issue, thanks
ps: earlier installed pil imaging-1.1.7 setup.py, later installed pillow, think problem in mutual presence of pil , pillow library on machine.
make sure "image.jpg" in same directory "test1.py".
if isn't either move it, or put correct directory inside of image.open()
.
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