Image.open() cannot identify image file in python script file -


i trying execute script

from pil import image im = image.open("image.jpg") nx, ny = im.size 

it working fine when run in python shell

pytesser_v0.0.1]#env python >>> pil import image >>> im = image.open("image.jpg") <pil.jpegimageplugin.jpegimagefile image mode=rgb size=46x24 @ 0x7fa4688f16d0> 

but when put in test.py file , run python test.py getting error

file "test1.py", line 17, in <module>     im = image.open("image.jpg")   file "/usr/local/python.2.7.11/lib/python2.7/site-packages/pil/image.py", line 2309, in open     % (filename if filename else fp)) ioerror: cannot identify image file 'image.jpg' 

please me issue, thanks

ps: earlier installed pil imaging-1.1.7 setup.py, later installed pillow, think problem in mutual presence of pil , pillow library on machine.

make sure "image.jpg" in same directory "test1.py".

if isn't either move it, or put correct directory inside of image.open().


Comments

Popular posts from this blog

javascript - Laravel datatable invalid JSON response -

java - Exception in thread "main" org.springframework.context.ApplicationContextException: Unable to start embedded container; -

sql server 2008 - My Sql Code Get An Error Of Msg 245, Level 16, State 1, Line 1 Conversion failed when converting the varchar value '8:45 AM' to data type int -