scanning a 2D char Array in C++ -

i trying scan 2d char array in c++ program. problem code not scan entire array expected. ex if want scan 41*41 array reason stops @ 40th row , when press enter scans 1 remaining row. here simple piece of code.

#include <iostream> char g[101][101]; int n,m; using namespace std; int main(int argc, const char * argv[]) {     cin >> m >> n;     cout << "m n scanned" << m << n << "\n"; (int t =0;t<m;t++) {     (int j = 0;j<n;j++) {         cin >> g[t][j];         cout << "scanned " << t << " " << j << "\n";     } } return 0; } 

compiling: testproj $g++ main.cpp -o main

what missing here?

edit: input 41 41 <2d char array of 41*41>

expected output: scanned 40 40

actual output scanned 39 40
press enter

....

scanned 40 40

works me.

input file, gets piped executed code on standard input:

41 41 ***************************************** *****************************************  [ 39 more rows of same ] 

output:

m n scanned4141 scanned 0 0 scanned 0 1 scanned 0 2  ...  scanned 40 36 scanned 40 37 scanned 40 38 scanned 40 39 scanned 40 40 

there's nothing wrong shown code, when used is.

i suspect forgot little detail operator>> on char values going skip whitespace, in addition newline characters, , input matrix contains spaces, ignored, , code continues 41*41 non-space characters read. so, @ point, code waiting read expected amount of unread non-whitespace input.